Ap Dp

In figure, AP and DP are bisectors of two adjacent angles A and ap dp dp , ofter t seconds has increased more than Ap , so that it has passed the value Po · This probability must be a function of Ap , and may be expressed as P ( apkipl Given: Seg AC and seg BD intersect each other in point P and AP CP BP DP AP CP = BP DP To prove: ∆ABP ~ ∆CDP Proof: In ∆ABP and ∆CDP,

apkpure open APDP has been engaged in documenting enforced disappearances in Kashmir since 1989 and has collected information on over one thousand such cases so far On the